To find these numbers wisely, we must see what we can deduce general characteristics. The only thing I can think is that the first number can only be 1, 2 or 3. Once
view this restriction, you have to start scoring. The best, in this case, is to start with the last digit of the first issue, since we can quickly calculate the last digit of the other two (and note whether or not we get and how much). After the penultimate digit, keeping an eye that does not generate repetitions, and then the first digit. Obviously, if generating the last or the second digit "spend" on 1, 2 and 3, we find no possible value for the former, as we said before.
Thus it is clear that the last digit can not be 1. If you look at 2, we find after some trial and error numbers 192, 384 and 576, which meet the statement.
If we exhaust all possibilities, we can continue testing for other possible last digits. By 3, we found 273, 546 and 819. The 4 does not provide any trio after playing a while. The 5 is immediately discarded. The probe 6 has cost me a lot and not find anything.
However, with 7 meeting 327, 654 and 981, and 257, 534 and 801. With 8 not get any fruit and the last I get to 9: 219, 438 and 657. In total five different possibilities meeting.
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