Statement
In a competition against the clock, it's almost over speed matter that rigor in reasoning, but it is important to find strategies to check and discard solutions which are not.
If we listen to the points given for each, the ideal would be to spend a little less than 2 minutes in the easy, 2 ½ minutes in the middle and just over 3 minutes difficult.
In the first, it is clear that 6 is the sum of two symbols Δ, so each must be 3. If we have to waste time changing the value proposed by check, you can also do, but be quick. The correct answer is D.
The second quickest way is to look at the two more like, 20 * 10 + 20 * 10 and 20 * 10 + 10 * 20. It is clear that they are equal, so we estimate its value (400) and try to find one that do not provide the same result. The single is 20/10 * 20 + 10, which gives 50. Therefore the correct answer is E.
In the third, I see it easier to divide the weight of moving between two on each branch, so that half will be worth 112 / 2 = 56. In the area where the star, divide again by 2, and comes 56 / 2 = 28 (square). Then divide again between 2 and is 14 (the triangle) and then we get the weight of the star again divide by 2, so it is worth 7 (response A).
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